aider moi en factorisation encore svp A(t)=(2t-1)(t+1)-2(t-1) B(t)=(t-4)2+(t-4)(2t+3) C(t)=(2t-1)(3t+5)+4t(3t+5) D(t)=(5t-1)(3t-2)-(5t-1)2
Mathématiques
sasa540
Question
aider moi en factorisation encore svp
A(t)=(2t-1)(t+1)-2(t-1)
B(t)=(t-4)2+(t-4)(2t+3)
C(t)=(2t-1)(3t+5)+4t(3t+5)
D(t)=(5t-1)(3t-2)-(5t-1)2
A(t)=(2t-1)(t+1)-2(t-1)
B(t)=(t-4)2+(t-4)(2t+3)
C(t)=(2t-1)(3t+5)+4t(3t+5)
D(t)=(5t-1)(3t-2)-(5t-1)2
1 Réponse
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1. Réponse loulakar
Bonjour,
A(t)=(2t-1)(t+1)-(2t-1)
A(t) = (2t - 1)(t + 1 - 1)
A(t) = t(2t - 1)
B(t)=(t-4)^2+(t-4)(2t+3)
B(t) = (t - 4)(t - 4 + 2t + 3)
B(t) = (t - 4)(3t - 1)
C(t)=(2t-1)(3t+5)+4t(3t+5)
C(t) = (3t + 5)(2t - 1 + 4t)
C(t) = (3t + 5)(6t - 1)
D(t)=(5t-1)(3t-2)-(5t-1)^2
D(t) = (5t - 1)(3t - 2 - 5t + 1)
D(t) = (5t - 1)(-2t - 1)