(x+3)² - (x+3)(2x-1)=0 (6x-1:7)(x+4)+(6x-1:7)(2x-3)=0

[tex](x+3)^2-(x+3)(2x-1)=0\\ \Leftrightarrow (x+3)(x+3-2x+1)=0\\ \Leftrightarrow (x+3)(-x+4)=0\\ \Leftrightarrow x= -3~ou~x=4[/tex]

[tex](6x-\frac{1}{7})(x+4)+(6x-\frac{1}{7})(2x-3)=0\\\\ \Leftrightarrow (6x-\frac{1}{7})(x+4+2x-3)=0\\\\ \Leftrightarrow (6x-\frac{1}{7})(3x+1)=0\\\\ \Leftrightarrow x = \frac{\frac{1}{7}}{6}=\frac{1}{42}~ou~x=-\frac{1}{3}[/tex]