Bonjour, J'ai un problème avec un exercice de mathématiques : Calculer les expressions suivantes lorsque : a = 2/3 ; b = - 3/2 ; c = - 3/4. M= 6 b² - 3 a + 5 N

M: 6*(-3/2)^2-2*(2/3)+5
=6*(9/4)-(4/3)+5
=(54/4)-(4/3)+5
=(162/12)-(16/12)+(60/12)
=(146/12)+(60/12)
=(206/12) =103/6

N:((2/3)+(-3/4))/((2/3)-(-3/2))
=((8/12)-(9/12))/((4/6)+(9/6))
=;-(1/12))/(13/6)
= (-1/12)*(6/13)
=-6/156
=-3/78 =-1/26

P:(2/3)-(3/2)+2*(3/4)-2*(-3/2+3/4)+2/3
=(8/12)-(18/12)+(6/4)-2*(-6/4+3/4)+8/12
=(8/12)-(18/12)+(18/12)+(18/12) +(8/12)
=54/12= 27/6 = 9/2

M=b2-3a+5 avec a=2/3, b=-3/2, c=-3/4 On a: M=(-3/2 x (-3/2) -3(2/3) + 5 M= 9/4 - 2 + 5 M= 9/4 + 3 N= a+c/a-b N= (2/3-3/4)/(2/3+3/2) N= -1/12)