résoudre cette equation x(-2x+3)+x(x+2)=0 (7x+3)(2x+1)-x(7x+3)=0

x(-2x + 3) + x(x + 2) = 0
-2x² + 3x + x² + 2x = 0
x² + 5x = 0
x(x + 5) = 0
Soit : x = 0
Soit : x+5 = 0
         x = -5

(7x + 3)(2x + 1) - x(7x + 3) = 0
(7x + 3)(2x + 1 - x) = 0
(7x + 3)(x + 1) = 0
Soit : 7x + 3 = 0
         7x = -3
         x = -[tex] \frac{3}{7} [/tex]
Soit : x + 1 = 0
         x = -1

-2x+3x+x²+2x = 0
x²+3x = 0
x(x+3) = 0

x+3  = 0
x = -3

x = 0


on factorise :

(7x+3)(2x+1-x) = 0
(7x+3)(x+1) = 0

7x+3 =0
7x =-3
x =-3/7

x+1 = 0
x = -1