Mathématiques

Question

Aidez moi svp c hyper urgent
Aidez moi svp c hyper urgent

2 Réponse

  • 1) -2x²+23x-30 = 0

    b²-4ac = 23²-4(-2*-30) = 23²-4(60) = 529-240 = 289
    Δ>0  2solutions

    x1 = -b+√Δ/2a = -23+17/-4 = -6/-4 = 3/2
    x2 = -b-√Δ/2a )= -23-17/-4 = -40/-4 = 10

    b) 20-9² = 4
    -9x²+16 = 0

    b²-4ac = 16²-4(-9*0) = 16² =256
    Δ>0, 2solutions
    x1 =-b+VΔ/2a = -16+16/-18 = 0
    -x2=b-√Δ/2a = -16-16/18  =-32/18  =-16/9

    c) -x²-5 = x²
    -2x²-5 = 0

    b²-4ac = (-5)²-4(-2*0) = 25
    Δ>0 2solutions
    x1 -b-√Δ/2a  =  -5+5/-4 = 0
    x² = b-√Δ/2a = +5+5/-4 = -10/4 = -5/2

    d) x²+9X+25 = x
    x²+10x+25 = 0
    b²-4ac =  +10²-4(1*25) = 100-100 = 0
    Δ=0, 1 solution
    -b/2a = -10/2 = -5

  • je c pas trop on voit pas