Mathématiques

Question

3-(4a-7)=6-5(12-8a) ??
-4(a+5)-6(12a-30)=0 ??

2 Réponse

  • 3-(4a-7)=6-5(12-8a)
    3 - 4a + 7 = 6 - 60 + 40a
    - 4a - 40a = 6 - 60 - 3 - 7
    - 44a = - 64
    a =  64/44
    a = 4 x  16 / 4 x 11
    a =  16/11


    - 4 (a + 5) - 6 (12a - 30) = 0
    - 4a - 20 - 72a + 180 = 0
    - 4a - 72a = - 180 + 20
    - 76a = - 160
    a = 4 x - 40 / 4 x - 19
    a = 40/19
  • -4(a+5) - 6(12a -30) = 0
    -4a -20 -72a +180 = 0
    -76a + 160=0
    -76a = - 160
    a = 160/76  = 80 / 38  = 40 / 19

    3-(4a-7)=6-5(12-8a) 

    3 - 4a +7 = 6 -60 +40 a
    10 -4a = -54 + 40a
    -4a -40 a = -54 -10
    -44a = -64
    a = 64/44  = 32/22  = 16/11

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